采用固相法合成了KSr4(BO3)3∶xEu2+ (KSB∶xEu2+)荧光粉, 通过X射线粉末衍射(XRD)、扫描电镜(SEM)及光致发光光谱分别研究了样品的晶相、形貌及发光性质。XRD研究结果表明制备的样品为正交晶系的KSr4(BO3)3单相。当Eu2+的掺杂摩尔分数x为1.5%时, 在激发光谱250~550 nm范围内观察到了两个宽带激发, 可归属为Eu2+的4f7-4f65d1跃迁;在400 nm激发下, 发射谱呈现出一个不对称的黄色发射带, 峰值位于560 nm处, 可归属于Eu2+的4f65d1-4f7跃迁。因在KSr4(BO3)3化合物中存在3个Sr格位, 根据其光谱特征可推测发射谱中非对称的发射带来源于多个Eu2+发光中心。

KSr4(BO3)3∶xEu2+ (KSB∶xEu2+) phosphors were synthesized by solid-state reaction method. The phase, morphology, and luminescence properties of the samples were characterized by using XRD, SEM, and photoluminescence spectra. XRD results show that the as-prepared samples are orthorhombic KSr4(BO3)3 single-phase. When x=1.5%, two broad bands are observed from 250 to 550 nm in the excitation spectra, which are attributed to 4f7-4f65d1 transition of Eu2+. Under the excitation of 400 nm, the emission spectrum shows an asymmetric yellow emission band around 560 nm, attributed to 4f65d1-4f7 transition of Eu2+. Because of three Sr crystallographic sites in KSr4(BO3)3 compound, one can infer that the asymmetric emission results from multiple Eu2+ centers by the spectral characteristics.