以氧化铋、四水氯化锰为原料,盐酸为溶剂,采用水解法制备了Mn与Bi具有不同摩尔比率的Mn-BiOCl光催化剂.采用X射线衍射(XRD)、高分辨透射电子显微镜(HRTEM)、透射电子显微镜(TEM)、紫外-可见漫反射光谱(UV-Vis DRS)、电子衍射(SAED)、表面光电压光谱(SPS)等对其进行了表征.以甲基橙为光催化反应模型化合物,评价了Mn-BiOCl光催化剂的紫外光催化活性.并研究了甲基橙降解过程中的活性物种.结果表明:Mn的含量对Mn-BiOCl光催化剂的催化活性有重要影响.当Mn与Bi的物质的量之比为0.25% 时,制备的Mn-BiOCl光催化剂催化活性最高,甲基橙的光催化降解率达到95.1%。

Using Bi2O3 and MnCl2·4H2O as raw materials,with HCl as solvent,photocatalysts of Mn-BiOCl with different molar ratio of Mn and Bi were prepared by a hydrolysis method.The obtained samples were characterized by XRD,HRTEM,TEM,UV-Vis DRS and SPS.The UV light photocatalytic activity of Mn-BiOCl was evaluated by using methyl orange as model compounds of photocatalytic reaction.The active species in the degradation process of methyl orange were studied.The results show that the Mn content of Mn-BiOCl photocatalysts has an important effect on the catalytic activity.When the molar ratio of Mn and Bi is 0.25%,the as-prepared Mn-BiOCl photocatalyst has the highest catalytic activity toward the degradation of methyl orange.Photocatalytic degradation rate of methyl orange can reach 95.1%.